CSIR UGC NET 2019 Online Form; (December) Session Dates Released! Check Details
CSIR UGC NET
National Testing Agency (NTA) has recently announced an official notification on its official website related to CSIR UGC NET 2019 Online Form for December 2019 and June 2020 Sessions. CSIR-UGC NET Examination for December 2019 Session will organize on 15th December 2019 whereas CSIR-UGC NET June 2020 Session Exam will be held on 21st June 2020. Interested candidates can submit online form by below link. The Link of CSIR UGC NET December online form will be activated on 09 September 2019 and the last date to apply is 09th October 2019.
Candidates can also apply for CSIR UGC NET 2019 Exam by follow the below given steps in this page or also find more information about CSIR UGC NET 2019 Exam Notification such as educational qualification, application fee, procedure to apply or more.
CSIR UGC NET 2019 Exam Overview:
| Conducting Body | National Testing Agency (NTA) |
| Exam Name | CSIR UGC NET 2019 December |
| Starting Date to Apply | 09th September 2019 |
| Last Date to Apply | 09th October 2019 |
| Downloading of Admit Card | 09th November 2019 |
| Joint CSIR-UGC NET Exam Dec Date | 15th December 2019 |
| Date of Announcing CSIR Dec UGC NET Exam Result | 31st December 2019 |
| Mode to Apply | Online |
| Official Website | csirhrdg.res.in |
CSIR UGC NET Eligibility Criteria 2019
Applicants satisfying the following conditions are allowed to fill CSIR NET 2019 Application Form:
The upper age limit for Junior Research Fellow (JRF) must be 28 years.
No upper age limit for Lectureship.
Relaxation will be provided as rules and regulation of government.
Candidates should have completed BS-four year’s program that is B.Pharm, B.E, B. Tech, MSc, MBBS, Integrated BS-MS or any other science degree with at least 55% marks for general category and 50% marks for reserved category.
Those who have completed/studying M.Sc and have completed their graduation (10+2+3) are also eligible.
B.Sc. or integrated MS-PhD program and have secured at least 55% marks are also eligible.
Bachelor degree from any science stream or engineering can also get the fellowship but only after being registered to PhD or PhD integrated program.
Concession of 5% marks will be permitted to reserved category candidates.
Candidates, who have completed their Ph.D. prior 19 September 1992, are also eligible to apply for CSIR UGC National Eligibility Exam 2019.
CSIR UGC NET JRF Stipend
The candidates selected for the JRF post through CSIR-UGC National Eligibility Test (NET) will be offered Rs.25, 000/ p.m. for the first two years. Along with this, annual contingency grant of Rs.20000/- per fellow will be provided to the University / Institution.
CSIR UGC NET Application Fee
The following amount of examination charges is to be paid through Debit/Credit Card /Net Banking/NEFT while applying for CSIR NET 2019 Exam
| Category | Examination Fee |
| General | Rs.1000/- |
| OBC (Non-creamy layer) | Rs.500/- |
| SC/ST/PWD | Rs.250/- |
CSIR UGC NET Exam Pattern 2019
Look at the salient features of CSIR UGC NET 2019 Dec Examination given in the following section. Also, CSIR NET Exam Pattern 2019 is summarized in the tabular form which is given below.
A single paper MCQ based test will be held.
The Test Booklet will be printed in Hindi & English Version.
The Test Booklet shall be divided into three parts (A, B & C).
Total marks: 200.
Exam Duration: 3 hours.
Negative marking shall be applicable as per subject wise scheme of Exam.
No grievances/representation with regard to Answer Key(s) after the declaration of result will be entertained.
| Parts | Subjects | Number of Questions |
| A |
General
Aptitude, Graphical Analysis, Logical Reasoning, Numeric Ability etc. | 200 |
| B | Mathematics and Engineering Aptitude | |
| C |
Application
of the scientific concepts, Engineering Sciences | |
| Duration | 3 hours |
Subjects of CSIR UGC NET 2019
| No. | Subject |
| I | Life Sciences |
| II | Earth, Atmospheric, Ocean and Planetary Sciences |
| III | Mathematical Sciences |
| IV | Chemical Sciences |
| V | Physical Sciences |
Session and Timings
| Session | Timings |
| Morning Session | 9.00AM – 12.00 Noon |
| Afternoon Session | 2.00 PM – 5.00 PM |
CSIR UGC NET Cut Off Marks 2019
The cutoff accounts for the minimum marks required to qualify CSIR UGC NET to be enrolled for fellowships.
Cut Off marks is expected to be declared separately for each subject.
| Cut-Off | JRF | LS |
| General | 120 | 110 |
| OBC | 110 | 100 |
| SC /ST | 100 | 90 |
Expected Cut Off for Junior Research Fellowship:
| Name of the Subject | Unreserved | OBC | SC |
| Chemical Science | 55.50 % | 48.25 % | 40.25 % |
|
Earth Science | 53.72 % | 46.06 % | 38.61 % |
| Life Science | 55.00 % | 45.00 % | 37.00 % |
|
Mathematical Science | 50.38 % | 42.88 % | 34.13 % |
| Physical Science | 40.63 % | 34.88 % | 29.25 % |
| Name of the Subject | ST | PWD |
| Chemical Science | 30.00 % | 28.75 % |
|
Earth Science | 32.60 % | 25.00 % |
| Life Science | 31.50 % | 25.00 % |
|
Mathematical Science | 25.00 % | 25.00 % |
| Physical Science | 25.00 % | 25.00 % |
Expected Cut Off for Lecturership (NET)
| Name of the Subject | Unreserved | OBC | SC |
| Chemical Science | 49.95 % | 43.43 % | 36.22 % |
|
Earth Science | 48.35 % | 41.45 % | 34.75% |
| Life Science | 49.50 % | 40.50 % | 33.30 % |
|
Mathematical Science | 45.34 % | 38.59 % | 30.72 % |
| Physical Science | 36.57 % | 33.00 % | 26.32 % |
| Name of the Subject | ST | PwD |
| Chemical Science | 27.00 % | 25.87 % |
|
Earth Science | 29.34 % | 25.00 % |
| Life Science | 28.35% | 25.00 % |
|
Mathematical Science | 25.00 % | 25.00 % |
| Physical Science | 25.00 % | 25.00 % |
Examination Centres
The test will be held at 27 Centres spread all over India, as specified below:
| Bangalore Bhavnagar Bhopal Bhubaneshwar Chandigarh Chennai Cochin Delhi Guntur | Guwahati Hyderabad Imphal Jammu Jamshedpur Jorhat Karaikudi Kolkata Lucknow | Nagpur Pilani Pune Raipur Roorkee Srinagar Thiruvananthapuram Udaipur Varanasi |
How to fill CSIR UGC NET Application Form 2019?
- First of all, visit official portal of organization i.e. www.csirhrdg.res.in for CSIR UGC NET apply online.
- Now go to link for CSIR UGC for JRF/LS December, 2019 given on the homepage.
- Now hit on the link specified as CSIR UGC NET exam notification-
- Then fill CSIR UGC NET 2019 Registration Form.
- After CSIR UGC NET registration, you may download CSIR UGC NET Application Form 2019.
- Put all details in CSIR UGC NET Online Application Form 2019.
- Also, upload required documents along with CSIR UGC Application Form as need arises.
- After filling the online application, two options will appear at the bottom of the page, “Save and Preview” and “Reset”.
- If you select “Reset”, the entire information you have filled will be erased and you will have to fill the form afresh.
- If you select “Save and Preview”, two options “Edit Application” and “Final Submit and Proceed for Fee Payment” will appear.
- Here, you can view the information that you have filled in the CSIR NET Application Form 2019.
- After checking all details filled in form, you may submit your CSIR UGC National Eligibility Test 2019 Application Form.
- At last, take a hard copy of CSIR UGC NET application online form for further usage.
For more details about CSIR UGC NET Online Form, click on this Official Link.
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